Electric bulb $50\, W$ - $100\, V$ glowing at full power are to be used in parallel with battery $120\, V$, $10 \,\Omega$. Maximum number of bulbs that can be connected so that they glow in full power is
Diffcult
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(c) When each bulb is glowing at full power,
Current from each bulb $ = i' = \frac{{50}}{{100}} = \frac{1}{2}\,A$
So main current $i = \frac{n}{2}\,A$
Also $E = V + ir$
$==>$ $120 = 100 + \left( {\frac{n}{2}} \right) \times 10 \Rightarrow n = 4$
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