$R = \frac{{{V^2}}}{P} = \frac{{200 \times 200}}{{100}} = 400\,\Omega $.
So resistance when lamp not in use.
${R_{Cold}} = {\rm{ }}\frac{{{R_{Hot}}}}{{10}} = \frac{{400}}{{10}} = 40\,\Omega $

The value of $x$ to the nearest integer is .........
$[1]$ battery emf is increased
$[2]$ all resistances are increased by $10\,ohms$
$[3]$ all resistances are made five times
$[4]$ the battery and the galvanometer are interchanged


