Consider the situation shown in the figure. The capacitor $A$ has a charge $q$ on it whereas $B$ is uncharged. The charge appearing on the capacitor $B$ a long time after the switch is closed is
IIT 2001, Easy
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(a) The $ \pm q$ charges appearing on the inner surfaces of $A$, are bound charges. As $B$ is uncharged initially, as it is isolated, the charges on $A$ will not be affected on closing the switch $S$. No charge will flow in to $B$.
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