$Cu^+ /Cu = + 0.52\, V$,
$Fe^{3+} /Fe^{2+} = +0.7 7\, V$,
$\frac{1}{2}{I_2}\left( s \right)/{I^ - }\, = + 0.54\,V,$
$Ag^+ /Ag = + 0.88\,V$.
Based on the above potentials, strongest oxidizing agent will be
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$\mathrm{NaOH}+\mathrm{Cl}_{2} \rightarrow(\mathrm{A})+$ side products
(hot and conc.)
$\mathrm{Ca}(\mathrm{OH})_{2}+\mathrm{Cl}_{2} \rightarrow(\mathrm{B})+$ side products
$(dry)$
| $[R]$ (molar) | $1.0$ | $0.75$ | $0.40$ | $0.10$ |
| $\mathrm{t}$ (min.) | $0.0$ | $0.05$ | $0.12$ | $0.18$ |
The order of the reaction is
