Element A reacts with aqueous NaOH solution to form B and H . Aqu… - Vidyadip

Question

Element A reacts with aqueous NaOH solution to form B and H . Aqueous solution of B is hetated to $323-33 \mathrm{~K}$ and on passing $\mathrm{CO}_2$ into it, $\mathrm{Na}_2 \mathrm{CO}_3$ and C were formed. When C is heated to $1200^{\circ} \mathrm{C}, \mathrm{Al}_2 \mathrm{O}_3$ is formed. identify A,B, and C and also write the reaction involved.

✓

Answer

The reaction involved are as follow.
$2 \mathrm{Al}+2 \mathrm{NaOH}+2 \mathrm{H}_2 \mathrm{O} \longrightarrow 2 \mathrm{NaAlO}_2+3 \mathrm{H}_2 \uparrow$
$2 \mathrm{NaAlO}_2+\mathrm{CO}_2+3 \mathrm{H}_2 \mathrm{O} \xrightarrow[\Delta]{\Delta}+\mathrm{Na}_2 \mathrm{O}_3+2 \mathrm{Al}(\mathrm{OH})_3$
$2 \mathrm{Al}(\mathrm{OH})_3 \xrightarrow{1200^{\circ} \mathrm{C}} \mathrm{Al}_2 \mathrm{O}_3+3 \mathrm{H}_2 \mathrm{O}$
Thus, $\mathrm{A}, \mathrm{B}$, and C are $\mathrm{Al}, \mathrm{NaAlO}_2$ and $\mathrm{Al}(\mathrm{OH})_3$ respectively.

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