MCQ
Enthalpy change of the reaction $4H(g) \to 2H_2(g)$ is $-869.6\, kJ$. The bond dissociation energy of $H-H$ bond is .....$kJ$
- A$-434.8$
- ✓$+ 434.8$
- C$-869.6$
- D$+ 217.4$
$2 \mathrm{H}_{2} \longrightarrow 4 \mathrm{H}, \quad \Delta \mathrm{H}=+869.6\, \mathrm{kJ}$
$2 \times \mathrm{BE}_{\mathrm{H}-\mathrm{H}}=869.6 \,\mathrm{kJ}$
$\mathrm{BE}_{\mathrm{H}-\mathrm{H}}=\frac{869.6}{2}=434.8 \,\mathrm{kJ}$
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