MCQ
The hybridisation in $B{F_3}$ molecule is
- A$sp$
- ✓$s{p^2}$
- C$s{p^3}$
- D$s{p^3}d$
✓
Answer
Correct option: B.
$s{p^2}$
(b) In the formation of $B{F_3}$ molecule, one $s$ and $2p$ orbital hybridise.
Therefore it is $s{p^2}$ hybridization.
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