MCQ
Equivalent weight of $KMn{O_4}$ acting as an oxidant in acidic medium is equal to
  • A
    Molecular weight of $KMn{O_4}$
  • B
    $\frac{1}{2}×$ Molecular weight of $KMn{O_4}$
  • C
    $\frac{1}{3}×$ Molecular weight of $KMn{O_4}$
  • $\frac{1}{5}×$ Molecular weight of $KMn{O_4}$

Answer

Correct option: D.
$\frac{1}{5}×$ Molecular weight of $KMn{O_4}$
d
(d)$\frac{1}{5} \times {\rm{ molecular }}\,\,{\rm{weigth of }}KMn{O_4}$

as transfer of $5{e^ - }$ takes place when $KMn{O_4}$ acts as oxidant in acidic medium.

$2KMn{O_4} + 3{H_2}S{O_4} \to {K_2}S{O_4} + 2MnS{O_4} + 3{H_2}O$$ + 5O$

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