MCQ
Equivalent weight of $KMn{O_4}$ acting as an oxidant in acidic medium is equal to
- AMolecular weight of $KMn{O_4}$
- B$\frac{1}{2}×$ Molecular weight of $KMn{O_4}$
- C$\frac{1}{3}×$ Molecular weight of $KMn{O_4}$
- ✓$\frac{1}{5}×$ Molecular weight of $KMn{O_4}$
