This deep blue coloured complex has the following structure
Oxidation state of \(Cr\) is \(+6\) due to the presence of two peroxide linkages which can be calculated as \(Cr\) peroxide normal \(x+(-1) 4+(-2)=0, x-6=0\) and \(x=+6\)
$5{H_2}{O_2} + \,xCl{O_2}\, + 2O{H^ - }\, \to \,xC{l^ - }\, + \,y{O_2} + 6{H_2}O$