\( \Rightarrow \frac{\mathrm{m}}{135}=\frac{9.3}{93} \)
\( \Rightarrow \mathrm{m}=13.5 \mathrm{~g}\)
${C_2}{H_5}N{H_2}\,\xrightarrow{{HN{O_2}}}a$
${C_2}{H_5}N{H_2}\,\xrightarrow{{{C_6}{H_5}CHO}}b$
${C_2}{H_5}N{H_2}\,\xrightarrow{{NOCl}}c$
${C_2}{H_5}N{H_2}\,\xrightarrow{{{C_6}{H_5}S{O_2}Cl}}d$
$PhC{{O}_{2}}H\xrightarrow[2.\,N{{H}_{3}}]{1.\,PC{{l}_{5}}}A\xrightarrow[2.\,{{H}_{2}}/Ni]{1.\,{{P}_{4}}{{O}_{10}}.heat}B.$ અંતિમ નીપજ $(B)$ શું હશે ?
જ્યાં $\underset{(i)}{\mathop{\gamma =C{{H}_{3}}CO_{2}^{-},}}\,\,\,\,\,\,\underset{(ii)}{\mathop{Cl-C{{H}_{2}}-CO_{2}^{-},}}\,\,\,\,\,\,\,\underset{(iii)}{\mathop{Ph-SO_{3}^{-}}}\,$