Question
Estimate the time taken by the oscillating pendulum to shift from x = 0 to $\text{x}=\frac{\text{A}}{2}$ where A is the amplitude.
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Answer
Since initial position at t = 0 is x = 0 We represent S.H.M. by $\text{x = A}\sin\omega\text{t}$ When $\text{x}=\frac{\text{A}}{2},\frac{\text{A}}{2}=\text{A}\sin\omega\text{t}$$\therefore\omega\text{t}=\frac{\pi}{6},\text{t}=\frac{\text{T}}{12}$
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