Question
Evaluate:
$ (105)^2- (104)^2$
$ (105)^2- (104)^2$
✓
Answer
We have,
$(n+1)^2-n^2=(n+1)+n$
Taking $n = 104$ and $(n + 1) = 105$
We get,
$(105)^2- (104)^2= (105 + 104) = 209$
$(n+1)^2-n^2=(n+1)+n$
Taking $n = 104$ and $(n + 1) = 105$
We get,
$(105)^2- (104)^2= (105 + 104) = 209$
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