Question
Evaluate: $-3+\frac{1}{8}+\frac{-2}{5}$
✓
Answer
$-3+\frac{1}{8}+\frac{-2}{5}$
$LCM$ of $8, 5 = 40$
$\frac{-3}{1}=\frac{-3\times40}{1\times40}=\frac{-120}{40}$
$\frac{1}{8}=\frac{1\times5}{8\times5}=\frac{5}{40}$
$\frac{-2}{5}=\frac{-2\times8}{5\times8}=\frac{-16}{40}$
$\therefore \ \frac{-3}{1}+\frac{1}{8}+\frac{-2}{5}$
$=\frac{-120}{40}+\frac{5}{40}+\frac{-16}{40}$
$=\frac{-120+5+(-16)}{40}$
$=\frac{-120+5+(-16)}{40}=\frac{-136+5}{40}$
$=\frac{-131}{40}$
$LCM$ of $8, 5 = 40$
$\frac{-3}{1}=\frac{-3\times40}{1\times40}=\frac{-120}{40}$
$\frac{1}{8}=\frac{1\times5}{8\times5}=\frac{5}{40}$
$\frac{-2}{5}=\frac{-2\times8}{5\times8}=\frac{-16}{40}$
$\therefore \ \frac{-3}{1}+\frac{1}{8}+\frac{-2}{5}$
$=\frac{-120}{40}+\frac{5}{40}+\frac{-16}{40}$
$=\frac{-120+5+(-16)}{40}$
$=\frac{-120+5+(-16)}{40}=\frac{-136+5}{40}$
$=\frac{-131}{40}$
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