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Exponents — MATHS STD 8 — Question

Gujarat BoardEnglish MediumSTD 8MATHSExponents2 Marks
Question
Evaluate: $\Big(\frac{-2}{3}\Big)^{-3}\times\Big(\frac{-2}{3}\Big)^{-2}$
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Answer

$\Big(\frac{-2}{3}\Big)^{-3}\times\Big(\frac{-2}{3}\Big)^{-2}$$=\Big(\frac{3}{-2}\Big)^{3}\times\Big(\frac{3}{-2}\Big)^{2}$
$=\frac{3^3}{-2^3}\times\frac{3^3}{-2^3}$
$=\frac{3^{(3+2)}}{-2^{(3+2)}}$
$=\frac{3^5}{-2^5}$
$=\frac{-243}{32}$

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