Question
Factorise:
$63x^2y^2- 7$
$63x^2y^2- 7$
✓
Answer
$= 7(9x^2y^2- 1)$
$= 7((3xy)^2- (1)^2)$
[according to the formula $a^2- b^2= (a + b)(a - b)]$
$= 7(3xy + 1)(3xy - 1)$
$= 7((3xy)^2- (1)^2)$
[according to the formula $a^2- b^2= (a + b)(a - b)]$
$= 7(3xy + 1)(3xy - 1)$
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