Question
Evaluate:
$\bigg\{\Big(\frac{3}{2}\Big)^{-2}\bigg\}^{2}$

Answer

$\bigg\{\Big(\frac{3}{2}\Big)^{-2}\bigg\}^{2}$$=\Big(\frac{3}{2}\Big)^{-2\times2}=\Big(\frac{3}{2}\Big)^{-4}$
$=\Big(\frac{2}{3}\Big)^{4}$
$=\frac{2}{3}\times\frac{2}{3}\times\frac{2}{3}\times\frac{2}{3}$
$=\frac{16}{81}$

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