Question
Evaluate $: \frac{\tan 47^{\circ}}{\cot 43^{\circ}}$
✓
Answer
$\frac{\tan 47^{\circ}}{\cot 43^{\circ}}$
$=\frac{\tan \left(90^{\circ}-43^{\circ}\right)}{\cot 43^{\circ}}$
$=\frac{\cot 43^{\circ}}{\cot 43^{\circ}}$
$=1$
$=\frac{\tan \left(90^{\circ}-43^{\circ}\right)}{\cot 43^{\circ}}$
$=\frac{\cot 43^{\circ}}{\cot 43^{\circ}}$
$=1$
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