Question
Evaluate the determinant $\left|\begin{array}{cc} {\cos \theta} & {-\sin \theta} \\ {\sin \theta} & {\cos \theta} \end{array}\right|$

Answer

We know that determinant of $A$ is calculated as $|A|=\left|\begin{array}{ll} {a} & {b} \\ {c} & {d} \end{array}\right| = ad - bc$
Now, $\left|\begin{array}{cc} {\cos \theta} & {-\sin \theta} \\ {\sin \theta} & {\cos \theta} \end{array}\right|$
$= \cos \theta(\cos \theta) - (-\sin \theta)(\sin \theta)$
$= \cos^2\theta + \sin^2\theta$
$= 1... [\because \cos^2\theta + \sin^2\theta = 1]$
$\therefore$ The determinant of the above matrix is $1.$

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