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Algebraic Identities — Maths STD 9 — Question

Maharashtra BoardEnglish MediumSTD 9MathsAlgebraic Identities3 Marks
Question
Evaluate the following using identities:
$117 \times 83$
✓

Answer

We have,
$117 \times 83$
$= (100 + 17)(100 - 17)$
$= (100)^2 - (17)^2[(a + b)(a - b) = a^2 - b^2]$
$= 10000 - 289 [Where a = 100 and b = 17]$
$= 9711$
Therefore, $117 \times 83 = 9711$

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