Question
Evaluate
(i) $(-2)^2 \times(-3)^3$
(ii) $(-3)^2 \times 4^3$
(i) $(-2)^2 \times(-3)^3$
(ii) $(-3)^2 \times 4^3$
✓
Answer
(i) We have, $(-2)^2 \times(-3)^3$
$\because \quad(-2)^2=(-2) \times(-2)=4$
and $\quad(-3)^3=(-3) \times(-3) \times(-3)=-27$
$\therefore(-2)^2 \times(-3)^3=4 \times(-27)=-108$
(ii) We have, $(-3)^2 \times 4^3$
$\because(-3)^2=(-3) \times(-3)=9$
and $4^3=4 \times 4 \times 4=64$
$\therefore(-3)^2 \times 4^3=9 \times 64=576$
$\because \quad(-2)^2=(-2) \times(-2)=4$
and $\quad(-3)^3=(-3) \times(-3) \times(-3)=-27$
$\therefore(-2)^2 \times(-3)^3=4 \times(-27)=-108$
(ii) We have, $(-3)^2 \times 4^3$
$\because(-3)^2=(-3) \times(-3)=9$
and $4^3=4 \times 4 \times 4=64$
$\therefore(-3)^2 \times 4^3=9 \times 64=576$
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