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5. Thermodynamics and thermochemistry — Chemistry STD 11 Science — Question

Gujarat BoardEnglish MediumSTD 11 ScienceChemistry5. Thermodynamics and thermochemistry1 Mark
MCQ
Which of the following condition favours the reduction of a metal oxide to metal?
  • A
    $\Delta H = +ve, T\Delta S = + ve$ at low temperature
  • B
    $\Delta H = +ve, T\Delta S = -ve$ at any temperature
  • C
    $\Delta H = -ve, T\Delta S = -ve$ at high temperature
  • ✓
    $\Delta H = -ve, T\Delta S = + ve$ at any temperature
✓

Answer

Correct option: D.
$\Delta H = -ve, T\Delta S = + ve$ at any temperature
d
As $\Delta G =\Delta H - T \Delta S$

So, for the reduction of a metal oxide, $\Delta G$ value must be negative, and this can only be achieved among all given possibilities of $\Delta H$ and $T \Delta S$ values, when the $\Delta H =- ve$ and $T \Delta S =+ ve$ at any temperature.

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