MCQ
Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is
  • $1:64$
  • B
    $1 : 4$
  • C
    $64:1$
  • D
    $1 : 2$

Answer

Correct option: A.
$1:64$
a
(a) $\Delta P = \frac{{4T}}{r}\; \Rightarrow \frac{{\Delta {P_1}}}{{\Delta {P_2}}} = 4$

$\therefore \;\frac{{{r_2}}}{{{r_1}}} = 4$ and $\frac{{{V_1}}}{{{V_2}}} = {\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^3} = \frac{1}{{64}}$

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