MCQ
Excess pressure of one soap bubble is four times more than the other. Then the ratio of volume of first bubble to another one is
- ✓$1:64$
- B$1 : 4$
- C$64:1$
- D$1 : 2$
$\therefore \;\frac{{{r_2}}}{{{r_1}}} = 4$ and $\frac{{{V_1}}}{{{V_2}}} = {\left( {\frac{{{r_1}}}{{{r_2}}}} \right)^3} = \frac{1}{{64}}$
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