Question
Expand:$\Big(\frac{4}{5}\text{a}-2\Big)^3$
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Answer
$\Big(\frac{4}{5}\text{a}-2\Big)^3$ $\Big(\frac{4}{5}\text{a}\Big)^3-(2)^3-3\Big(\frac{4}{5}\text{a}\Big)^2(2)+3\Big(\frac{4}{5}\text{a}\Big)(2)^2$ $=\frac{64}{125}\text{a}^3-8-\frac{96}{25}\text{a}^2+\frac{48}{5}\text{a}$
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