Explain electrolysis of sulphuric acid.

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$\rightarrow $ In the electrolysis of dilute Sulphuric acid only electrolysis of water occurs.
$\ce{2 H _2 O ( l ) \rightarrow O _2(g)+4 H ^{+}( aq )+4 e ^{-}} E _{\text {(cell) }}^{\ominus}=$
$+1.23 V$
$\rightarrow$ Electrolysis of concentrated sulphuric acid oxidise $\ce{SO _4^{-2}}$ ion $\ce{S _2 O _8^{-2}}$
$\ce{2 SO _4^{2-}( aq ) \rightarrow S _2 O _8^{2-}( aq )+2 e ^{-} } E _{(\text {cell })}^{\ominus}=1.96 V$

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Answer the following:
$(a)$ Give two examples of non-chemical process which obeys the first order kinetics.
$(b)$ The following results have been obtained during the kinetic studies for the reaction:
$P+2Q \rightarrow R + 2S$

Exp.	Initial P(mol/L)	Initial Q (mol/L)	Init. Rate of Formation of R(M min-1)
$1$	$0.10$	$0.10$	$3.0 \times 10^{-4}$
$2$	$0.30$	$0.30$	$9.0 \times 10^{-4}$
$3$	$0.10$	$0.30$	$3.0 \times 10^{-4}$
$4$	$0.10$	$0.40$	$6.0 \times 10^{-4}$

Determine the rate law expression for the reaction.