Question
Explain hyperconjugation in propene.
✓
Answer
$i.$ In propene, $CH_3 – CH = CH_2,$ one of the $sp^2$ hybridized carbon atom of the double bond is attached to $sp^3$ hybridized carbon atom of methyl group.
$ii.$ One of the $C-H$ bonds of the methyl group can align in plane of the $p$ orbital of $sp^2$ hybridized $C-$atom and the electrons constituting the $C-H$ bond in plane with this $p$ orbital can then be delocalized into the $p$ orbital.
$iii.$ Therefore, hyperconjugation arises due to the partial overlap of a $C-H$ bond with the $p$ orbital of an adjacent $sp^2$ hybridized carbon atom.
$iv.$ Hyperconjugation $($no bond resonance$)$ structures for propene can be represented as:
$ii.$ One of the $C-H$ bonds of the methyl group can align in plane of the $p$ orbital of $sp^2$ hybridized $C-$atom and the electrons constituting the $C-H$ bond in plane with this $p$ orbital can then be delocalized into the $p$ orbital.
$iii.$ Therefore, hyperconjugation arises due to the partial overlap of a $C-H$ bond with the $p$ orbital of an adjacent $sp^2$ hybridized carbon atom.
$iv.$ Hyperconjugation $($no bond resonance$)$ structures for propene can be represented as:
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