Question
Explain the formation of $BeCl_2.$
✓
Answer
Formation of $\mathrm{BeCl}_2$ :
$i. \mathrm{BeCl}_2$ molecule has one $\mathrm{Be}$ atom and two chlorine atoms.
$ii.$ Electronic configuration of $\mathrm{Be}$ is $1 s^2 2 s^2 2 \mathrm{p}_{\mathrm{z}}^0$. Electronic configuration of beryllium:
$iii.$ The $2s \ and \ 2p_z$ orbitals undergo $sp$ hybridization to form two $sp$ hybrid orbitals oriented at $180^\circ$ with each other. $2p_z$ orbitals of two chlorine atoms overlap with the sp hybrid orbitals to form two $sp-p \ \sigma$ bonds.
$Cl – Be – Cl$ bond angle is $180^\circ.$ The geometry of the molecule is linear.
Diagram:
$i. \mathrm{BeCl}_2$ molecule has one $\mathrm{Be}$ atom and two chlorine atoms.
$ii.$ Electronic configuration of $\mathrm{Be}$ is $1 s^2 2 s^2 2 \mathrm{p}_{\mathrm{z}}^0$. Electronic configuration of beryllium:
$iii.$ The $2s \ and \ 2p_z$ orbitals undergo $sp$ hybridization to form two $sp$ hybrid orbitals oriented at $180^\circ$ with each other. $2p_z$ orbitals of two chlorine atoms overlap with the sp hybrid orbitals to form two $sp-p \ \sigma$ bonds.
$Cl – Be – Cl$ bond angle is $180^\circ.$ The geometry of the molecule is linear.
Diagram:
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