Question
Explain Van't Hoff factor.

Answer

→ Van't Hoff introduced a factor i, known as the Van't Hoff factor, to account for the extent of dissociation or association. This factor i is defined as:
Image
→ Here abnormal molar mass is the experimentally determined molar mass and calculated colligative properties are obtained by assuming that the non-volatile solute is neither associated nor dissociated.
→ In case of association, value of i is less than unity while for dissociation it is greater than unity.
→ Inclusion of van't Hoff factor modifies the equations for colligative properties as follows:
→Relative lowering of vapour pressure of solvent,
$\frac{p_1^0-p_1}{p_1^0}= i \cdot \frac{n_2}{n_1}$
Elevation of Boiling point, $\Delta T_b=i K_b m$
Depression of Freezing point, $\Delta T_f=i K_f m$
Osmotic pressure of solution, $\pi=i n_2 R T / V$
→ $i$ for several strong electrolytes. For $KCI , NaCl$ and $MgSO _4, i$ values approach 2 as the solution becomes very dilute. As expected, the value of $i$ gets close to 3 for $K _2 SO _4$.
Salt* Values of i van't Hoff Factor
i for complete
dissociation of
solute
0.1 m0.01 m0.001 m
NaCl1.871.941.972.00
KCl1.851.941.982.00
$MgSO_{4}$1.211.531.822.00
$K_{2}SO_{4}$2.322.72.843.00

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