Download App

Factorisation of Polynomials — Maths STD 9 — Question

Maharashtra BoardEnglish MediumSTD 9MathsFactorisation of Polynomials2 Marks
Question
Factorise:$2\sqrt{3}\text{x}^2+\text{x}-5\sqrt{3}$
✓

Answer

$2\sqrt{3}\text{x}^2+\text{x}-5\sqrt{3}$$=2\sqrt{3}\text{x}^2+6\text{x}-5\text{x}-5\sqrt{3}$
$=2\sqrt{3}\text{x}\big(\text{x}+\sqrt{3}\big)-5\big(\text{x}+\sqrt{3}\Big)$
$=\big(\text{x}+\sqrt{3}\big)\big(2\sqrt{3}\text{x}-5\big)$

Need a full question paper?

Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.

Start Generating Free

Explore more

More "2 Mark Question" from Factorisation of Polynomials→Factorisation of Polynomials — all question types→Maths STD 9 question papers→Maharashtra Board STD 9 question papers→Maharashtra Board question paper generator→

Similar questions

Find the value to three place of decimals of each of the following. It is given that $\sqrt2=1.414,\ \sqrt3=1.732,\ \sqrt5=2.236,\ \sqrt10=3.162.$$\frac{2+\sqrt{3}}{3}$
→
Factorise:$\text{x}^2+\sqrt{2}\text{x}-24$
→
Simplify:$\Big(16^{-\frac{1}{5}}\Big)^{\frac{5}{2}}$
→
Find the reduced form of the ratio of the first quantity to second quantity : 7 minutes 20 seconds, 5 minutes 6 seconds
→
Using the protractor, draw a right angle. Bisect it to get an angle of measure 45°.
→
Define the following terms:
Concurrent lines.
→
The mean of marks scored by 100 students was found to be 40. Later on, it was discovered that a score of 53 was misread as 83. Find the correct mean.
→
Find the value of a for which $(x-4)$ is a factor of $\left(2 x^3-3 x^2-18 x+a\right)$.
→
Simplify:$\Bigg(\frac{15^\frac{1}{4}}{3^\frac{1}{2}}\Bigg)^{-2}$
→
Point P is the midpoint of seg CD. If CP = 2.5, find l(CD).
→