Question
Factorise:
$(2 x-3)^2-8 x+12$
$(2 x-3)^2-8 x+12$
✓
Answer
$(2 x-3)^2-8 x+12$
$=(2 x-3)^2-4(2 x-3)$
$=(2 x-3)(2 x-3-4)$
$=(2 x-3)(2 x-7)$
$=(2 x-3)^2-4(2 x-3)$
$=(2 x-3)(2 x-3-4)$
$=(2 x-3)(2 x-7)$
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