Question
Factorise:
$32 x^4-500 x$

Answer

$32 x^4-500 x$
$=4 x\left(8 x^3-125\right)$
$=4 x\left[(2 x)^3-(5)^3\right]$
$=4 x\left[(2 x-5)\left((2 x)^2+2 x \times 5+(5)^2\right] \text { Since } a^3-b^3=(a-b)\left(a^2+a \times b+b^2\right)\right.$
$=4 x(2 x-5)\left(4 x^2+10 x+25\right)$

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