Question
Factorise:
$4 x^2-9 y^2-2 x-3 y$

Answer

$4 x^2-9 y^2-2 x-3 y$
$=(2 x)^2-(3 y)^2-(2 x+3 y)\left[\therefore a^2-b^2=(a-b)(a+b)\right]$
$=(2 x+3 y)(2 x-3 y)-(2 x+3 y)$
$=(2 x+3 y)(2 x-3 y-1)$

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