Question
Factorise: $p^4– 81$

Answer

$p^4-81$
$=\left(p^2\right)^2-(9)^2$
$\left(p^2-9\right)\left(p^2+9\right) . . . .$[Using Identity $III$
$ =\left\{(p)^2-(3)^2\right\}\left(p^2+9\right)$
$=(p-3)(p+3)\left(p^2+9\right). . . .$[Using Identity $III$

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