Question
Factorise: $\text{z}^2+\text{z}+\frac{1}{4}$

Answer

$\text{z}^2+\text{z}+\frac{1}{4}$ $=(\text{z})^2+2\times\text{z}\times\frac{1}{2}+\Big(\frac{1}{2}\Big)^2$ $=\Big(\text{z}+\frac{1}{2}\Big)^2$

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