Question
Factorise the following, using the identity $\mathrm{a}^2-2 \mathrm{ab}+\mathrm{b}^2=(\mathrm{a}-\mathrm{b})^2$.
$4 a^2-4 a b+b^2$

Answer

$4 a^2-4 a b+b^2$
$ =(2 a)^2-2 \times 2 a \times b+b^2 $
$ =(2 a-b)^2 $
$ =(2 a-b)(2 a-b)$

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