\(\Delta H=\Delta E+\Delta n_{g} R T\)
Where,
\(\Delta n_{g}=\) total number of moles of gaseous products total number of moles of gaseous reactants
For the given reaction,
\(Fe _{2} O _{3}( s )+3 H _{2}( g ) \rightarrow 2 Fe ( s )+ H _{2} O (l)\)
\(\Delta n_{g}=0-3=-3\)
\(\therefore \Delta H=\Delta E+(-3) R T\)
\(\Delta H=\Delta E-3 R T\)
આપેલ : $\Delta H ^{\circ}=-54.07\,kJ\,mol ^{-1}$
$\Delta S ^{\circ}=10\,J\,K ^{-1}\,mol ^{-1}$
$(2.303 \times 8.314 \times 298=5705$ લો.)
$(I)\, q + W \,\,(II)\, q \,\,(III) \,W \,\,(IV)\, H - TS$