Figure shows three circular arcs, each of radius $R$ and total charge as indicated. The net electric potential at the centre of curvature is
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$\mathrm{V}_{\mathrm{net}}$ at center
${\mathrm{V}_{\mathrm{net}}=\frac{\mathrm{K}(3 \theta+\theta-2 \theta)}{\mathrm{r}}} $
${\mathrm{V}_{\mathrm{net}}=\frac{2 \theta}{4 \pi \varepsilon_{0} \mathrm{r}}=\frac{\theta}{2 \pi \varepsilon_{0} \mathrm{r}}}$
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