Question
Find $\frac{d y}{d x}$ if : $y=(1-x)(2-x)$

Answer

$
\begin{aligned}
y & =(1-x)(2-x) \\
& =2-3 x+x^2
\end{aligned}
$
Differentiating w.r.t. $x$, we get
$
\begin{aligned}
\frac{\mathrm{d} y}{\mathrm{~d} x} & =\frac{\mathrm{d}}{\mathrm{d} x}\left(2-3 x+x^2\right) \\
& =\frac{\mathrm{d}}{\mathrm{d} x}(2)-3 \frac{\mathrm{d}}{\mathrm{d} x}(x)+\frac{\mathrm{d}}{\mathrm{d} x}\left(x^2\right) \\
& =0-3(1)+2 x \\
& =-3+2 x
\end{aligned}
$

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