
Reason : The dipoles of a polar dielectric are randomly oriented.
$(A)$ $E_A^{\text {lnside }}=0$
$(B)$ $Q_A > Q_B$
$(C)$ $\frac{\sigma_A}{\sigma_B}=\frac{R_B}{R_A}$
$(D)$ $E_A^{\text {on sulface }} < E_B^{\text {on uurface }}$



Note: $V_{1,2,3,4}$ are the potential differences across $C_{1,2,3,4}$ and $Q_{1,2,3,4}$ are the final charges stored in $C_{1,2,3,4}$ respectively.