MCQ
Find number of electrons present in $34\,g$ of $NH_3(g)$. .....................$N_A$
- A$2$
- B$1$
- ✓$20$
- D$10$
✓
Answer
Correct option: C.
$20$
c
Moles of $\mathrm{NH}_{3}=\frac{34}{17}=2$ moles
Moles of $\mathrm{NH}_{3}=\frac{34}{17}=2$ moles
no. of $\mathrm{NH}_{3}$ molecules $=2 \times \mathrm{N}_{\mathrm{A}}$
one $\mathrm{NH}_{3}$ molecule contains $10$ electron total no. of electrons $=2 \times \mathrm{N}_{\mathrm{A}} \times 10=20\, \mathrm{N}_{\mathrm{A}}$
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