Find out current in $3\,\Omega $ resistance in given circuit
A$1.5\, A$
B$\frac{2}{3}\,A$
C$\frac{4}{3}\,A$
D$1\,A$
Medium
Download our app for free and get started
C$\frac{4}{3}\,A$
c $\mathrm{R}_{\mathrm{eq}}=[(4+2) \| 3]+5$
$=7\, \Omega$
$I=\frac{14}{7}=2 \,A$
$I_{1}=\frac{6}{9} \times 2=\frac{4}{3} \,A$
Download our app
and get started for free
Experience the future of education. Simply download our apps or reach out to us for more information. Let's shape the future of learning together!No signup needed.*
Say switches $S_1, S_2$ and so on upto $S_6$ are closed, one after other in order (first $S_1$, then $S_2$) at regular intervals of $1$ minute starting from $t = 0$. The graph of current versus time is best represented as
In the circuit shown, a meter bridge is in its balanced state. The meter bridge wire has a resistance $0.1\, ohm/cm$. The value of unknown resistance $X$ and the current drawn from the battery of negligible resistance is
We have a galvanometer of resistance $25\,\Omega $. It is shunted by a $2.5\,\Omega $ wire. The part of total current that flows through the galvanometer is given as
A battery of internal resistance $4$ $\Omega$ is connected to the network of resistances as shown. In order to give the maximum power to the network, the value of $R$ (in $\Omega $) should be
In the circuit shown, the reading of the Ammeter is doubled after the switch is closed. Each resistor has a resistance $1\,\Omega$ and the ideal cell has an $e.m.f.$ $10\,V$. Then, the Ammeter has a coil resistance equal to ............ $\Omega$
A meter bridge is set-up as shown, to determine an unknown resistance ' $X$ ' using a standard $10$ ohm resistor. The galvanometer shows null point when tapping-key is at $52 \ cm$ mark. The end-corrections are $1 \ cm$ and $2 \ cm$ respectively for the ends $A$ and $B$. The determined value of ' $X$ ' is