A battery of $6\,V$ is connected to the circuit as shown below. The current I drawn from the battery is:
A$1\,A$
B$2\,A$
C$\frac{6}{11}\,A$
D$\frac{4}{3}\,A$
JEE MAIN 2022, Medium
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A$1\,A$
a Balanced wheat stone bridge in circuit so there is no current in $5\,\Omega$ resistor so it can be removed from the circuit.
$R _{eq }=\frac{6 \times 12}{6+12}+2$
$=\frac{6 \times 12}{18}+2$
$R _{e q }=6\,\Omega$
$I =\frac{ V }{ R _{a q }}=\frac{6}{6}=1\,Amp$
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$A$ conductor is made of an isotropic material and has shape of a truncated cone. $A$ battery of constant emf is connected across it and its left end is earthed as shown in figure. If at a section distant $x$ from left end, electric field intensity, potential and the rate of generation of heat per unit length are $E, V$ and $H$ respectively, which of the following graphs is are correct?
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$(iii)$ From the '$r$' dependence of $E(r)$, obtain the potential $V(r)$ at $r$.
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For current entering at $A$, the electric field at a distance '$r$'
from $A$ is