MCQ
Find out equivalent capacitance between $A$ and $B$.
- A$\frac{{5A{\varepsilon _0}}}{{3d}}$
- ✓$\frac{{3A{\varepsilon _0}}}{{5d}}$
- C$\frac{{3A{\varepsilon _0}}}{{2}}$
- D$\frac{{2A{\varepsilon _0}}}{{3}}$
✓
Answer
Correct option: B.
$\frac{{3A{\varepsilon _0}}}{{5d}}$
b
Let $\mathrm{C}=\frac{\mathrm{A} \in_{0}}{\mathrm{d}} .$ Equivalent circuit
Let $\mathrm{C}=\frac{\mathrm{A} \in_{0}}{\mathrm{d}} .$ Equivalent circuit
$\frac{1}{C_{e q}}=\frac{1}{C}+\frac{2}{3 C}=\frac{5}{3 C}$
${C_{eq}} = \frac{{3C}}{5} = \frac{{3A{ \in _0}}}{{5d}}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
If a battery of voltage $V$ is connected across terminals $I$ of the block box shown in figure, an ideal voltmeter connected to terminals $II$ gives a reading of $V/2$, while if the battery is connected to terminals $II$, a voltmeter across terminals $I$ reads $V$. The black box may contain
→Which radiations will be most effective for the emission of electrons from a metallic surface?
The most commonly used material for making transistor is
A flexible wire bent in the form of a circle is placed in a uniform magnetic field perpendicular to the plane of the coil. The radius of the coil changes as shown in figure. The graph of induced $emf$ in the coil is respresented by
→The figure shows a region of length $'l'$ with a uniform magnetic field of $0.3\, T$ in it and a proton entering the region with velocity $4 \times 10^{5}\, ms ^{-1}$ making an angle $60^{\circ}$ with the field. If the proton completes $10$ revolution by the time it cross the region shown, $l$ is close to....... $m$
→(mass of proton $=1.67 \times 10^{-27} \,kg ,$ charge of the proton $\left.=1.6 \times 10^{-19}\, C \right)$
The minimum amount of energy required to emit electrons from a metal surface is called:
A small sphere of mass $m =\ 0.5\, kg$ carrying a positive charge $q = 110\ \mu C$ is connected with a light, flexible and inextensible string of length $r = 60 \ cm$ and whirled in a vertical circle. If a vertically upwards electric field of strength $E = 10^5 NC^{-1}$ exists in the space, The minimum velocity of sphere required at highest point so that it may just complete the circle........$m/s$ $(g = 10\, ms^{-2})$
→If the potential difference $V$ applied to the coolidge tube is doubled, then the cut off wavelength
→Assertion : Diamond glitters brilliantly.
Reason : Diamond does not absorb sunlight.
The work function of a metal is $2.3\, eV$ and the maximum kinetic energy of photo electrons is $0.3\, eV$ when photon is incident on it. Find the wavelength of incident photon.............. $\mathop {\rm{A}}\limits^o $
→