Question
Find the angles of an isosceles triangle whose equal angles and the non $-$ equal angles are in the ratio $3: 4.$
✓
Answer
The equal angles and the non$-$equal angle are in the ratio $3: 4$.
Let equal angles be $3 x$ each, therefore non$-$equal angle is $4 x$.
Angles of a triangle $=180^{\circ}$
$\Rightarrow 3 x +3 x +4 x =180^{\circ} $
$\Rightarrow 10 x =180^{\circ} $
$\Rightarrow x =18^{\circ}$
Therefore, $3 x=54^{\circ}$ and $4 x=72$
Angles $=54^{\circ}, 54^{\circ}$ and $72^{\circ}$.
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