Question
Find the area of triangle AGF
✓
Answer
$\begin{aligned} & \text { Area of a triangle }=\frac{1}{2}\left[\left(x_1 y_2+x_2 y_3+x_3 y_1\right)-\left(x_2 y_1+x_3 y_2+x_1 y_3\right)\right] \\ & \text { Area of } \triangle AGF =\frac{1}{2}[(-2.5-13.5-6)-(-13.5-1-15)] \\ & =\frac{1}{2}[-22-(-29.5)]\end{aligned}$
$\begin{aligned} & =\frac{1}{2}[-22+29.5] \\ & =\frac{1}{2} \times 7.5 \\ & =3.75 \text { sq.units }\end{aligned}$
$\begin{aligned} & =\frac{1}{2}[-22+29.5] \\ & =\frac{1}{2} \times 7.5 \\ & =3.75 \text { sq.units }\end{aligned}$
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