MCQ
Find the current in the $10\, \Omega$ resistance
- A$0.27\, A \,P_2$ to $P_1$
- B$0.03 \,A \,P_2$ to $P_1$
- ✓$0.45\, A \,P_2$ to $P_1$
- D$0.27\, A\, P_1$ to $P_2$
✓
Answer
Correct option: C.
$0.45\, A \,P_2$ to $P_1$
c
The circuit can be redrawn as:
The circuit can be redrawn as:
$\varepsilon_{\mathrm{eq}}=\frac{\frac{\varepsilon_{1}}{\mathrm{r}_{1}}+\frac{\varepsilon_{2}}{\mathrm{r}_{2}}}{\frac{1}{\mathrm{r}_{1}}+\frac{1}{\mathrm{r}_{2}}}=\frac{\frac{5}{2}+\frac{5}{2}}{\frac{1}{2}+\frac{1}{2}}$
$\varepsilon_{\mathrm{eq}}=5 \mathrm{\,V}$
$\frac{1}{r_{e q}}=\frac{1}{r_{1}}+\frac{1}{r_{2}}=\frac{1}{2}+\frac{1}{2} \Rightarrow r_{e q}=1 \,\Omega$
$\therefore \mathrm{i}=\frac{\varepsilon}{\mathrm{r}+\mathrm{R}}=\frac{5}{10+1}=0.45 \mathrm{\,A}$
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