Question
Find the difference:
$7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$
$7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$
✓
Answer
$7-4\frac{2}{3}=\frac{7}{1}-\frac{14}{3}$
LCM of 1 and 3 = 3
$\therefore\frac{7\times3}{1\times3}=\frac{21}{3}$
$\frac{7}{1}-\frac{14}{3}=\frac{21}{3}-\frac{14}{3}$
$=\frac{21-14}{3}=-\frac{7}{3}=2\frac{1}{3}$
LCM of 1 and 3 = 3
$\therefore\frac{7\times3}{1\times3}=\frac{21}{3}$
$\frac{7}{1}-\frac{14}{3}=\frac{21}{3}-\frac{14}{3}$
$=\frac{21-14}{3}=-\frac{7}{3}=2\frac{1}{3}$
Need a full question paper?
Generate a complete, print-ready paper with questions like this in minutes — across 16+ boards, with answer keys.
Explore more
Similar questions
Simplify the following:
$25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}$
→$25-\frac{1}{2}\big\{5+4-(3+2-\overline{1+3}\big)\big\}$
In figure, AD bisects A and AD and $\text{AD}\perp\text{BC}$.
→- Is $\triangle\text{ADB}\cong\triangle\text{ADC}?$
- State the three pairs of matching parts you have used in (i)
- Is it true to say that BD = DC?
Lines PQ and RS intersect at point M. m∠PMR = x°.What are the measures of ∠PMS, ∠SMQ and ∠QMR ?
Two equal sides of a triangle are each 5 metres less than twice the third side. If the perimeter of the triangle is 55 metres, find the lengths of its sides.
Is it possible to have a triangle, in which.
Each angle is greater than 60°?
Each angle is greater than 60°?
Solve the following equations. Check your result in case.
$\frac{2\text{m}+5}{3}=3\text{m}-10$
→$\frac{2\text{m}+5}{3}=3\text{m}-10$
The sum of two numbers is $\frac{-1}{3},$ If one of the numbers is $\frac{-12}{3}$ find the other.
→Two angles of a triangle are equal and the third angle is greater than each of those angles by 30°. Determine all the angles of the triangle.
There are only 25 paise coins in a purse. The value of money in the purse is Rs. 17.50. Find the number of coins in the purse.
one slde of a parallelogram ts 18 cm long and Its area Is $153 cm^2$. Ftnd the distance of the glven slde from Its opposlte side.
→