Question
In figure, AD bisects A and AD and $\text{AD}\perp\text{BC}$.
  1. Is $\triangle\text{ADB}\cong\triangle\text{ADC}?$
  2. State the three pairs of matching parts you have used in (i)
  3. Is it true to say that BD = DC?

Answer

  1. Yes, $\triangle\text{ADB}\cong\triangle\text{ADC},$ by ASA criterion of congruency.
  2. We have used $\angle\text{BAD}=\angle\text{CAD}$, $\angle\text{ADB}=\angle\text{ADC}=90^\circ$
  3. Since, $\text{AD}\perp\text{BC}$ and AD = DA.
  4. Yes, BD = DC since, $\triangle\text{ADB}\cong\triangle\text{ADC}$.

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