Question
Find the distance between the parallel lines 3x – 4y + 7 = 0 and 3x – 4y + 5 = 0

Answer

Here, $A=3, B=-4, C_1=7$ and $C_2=5$.
Hence, the required distance is $d=\frac{|7-5|}{\sqrt{3^{2}+(-4)^{2}}}=\frac{2}{5}$

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