Find the distance of the point (3, -5) from the line 3x - 4y - 26… - Vidyadip

Question

Find the distance of the point (3, -5) from the line 3x - 4y - 26 = 0

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Answer

According to the question,
Given line is 3x – 4y –26 = 0 ...(1)
Comparing (1) with general equation of line Ax + By + C = 0, we get
A = 3, B = – 4 and C = – 26.
Given point is $(x_{1,} y_1) = (3, –5)$. The distance of the given point from the given line is
$d=\frac{\left|\mathrm{A} x_{1}+\mathrm{B} y_{1}+\mathrm{C}\right|}{\sqrt{\mathrm{A}^{2}+\mathrm{B}^{2}}}=\frac{|3.3+(-4)(-5)-26|}{\sqrt{3^{2}+(-4)^{2}}}=\frac{3}{5}$

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