Question
Find the following products:
$(3 y-8) \times(5 y-1)$

Answer

$(3 y-8) \times(5 y-1)$
$= 3 y(5 y-1)-8(5 y-1)$
$= 15 y^2-3 y-40 y+8$
$= 15 y^2-43 y+8$

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